MCQOPTIONS
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| 1. |
The bus impedance matrix of a 4 – bus power system is given by\({Z_{bus}} = \left[ {\begin{array}{*{20}{c}} {j0.3435}&{j0.2860}&{j0.2723}&{j0.2277}\\ {j0.2860}&{j0.3408}&{j0.2586}&{j0.2414}\\ {j0.2723}&{j0.2586}&{j0.2791}&{j0.2209}\\ {j0.2277}&{j0.2414}&{j0.2209}&{j0.2791} \end{array}} \right]\)A branch having an impedance of j 0.2 Ω is connected between bus 2 and the reference Then the values of Z22,new and Z23,new of the bus impedance matrix of the modified network are respectively. |
| A. | j0.5408 Ω and j0.4586 Ω |
| B. | j0.1260 Ω and j0.0956 Ω |
| C. | j0.5408 Ω and j0.0956 Ω |
| D. | j0.1260 Ω and j0.1630 Ω |
| Answer» C. j0.5408 Ω and j0.0956 Ω | |