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1. |
The block shear strength at an end connection for shear fracture and tension yield is given by : |
A. | (A<sub>vg</sub>f<sub>y</sub>/ 3 <sub>m0</sub>)+(0.9A<sub>tn</sub>f<sub>u</sub>/ <sub>m1</sub>) |
B. | (A<sub>tg</sub>f<sub>y</sub>/ <sub>m0</sub>)+(0.9A<sub>vn</sub>f<sub>u</sub>/ 3 <sub>m1</sub>) |
C. | (0.9A<sub>vg</sub>f<sub>y</sub>/ 3 <sub>m0</sub>)+(A<sub>tn</sub>f<sub>u</sub>/ <sub>m1</sub>) |
D. | (0.9A<sub>tg</sub>f<sub>y</sub>/ 3 <sub>m0</sub>)+( A<sub>vn</sub>f<sub>u</sub>/ <sub>m1</sub>) |
Answer» C. (0.9A<sub>vg</sub>f<sub>y</sub>/ 3 <sub>m0</sub>)+(A<sub>tn</sub>f<sub>u</sub>/ <sub>m1</sub>) | |