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1. |
The area of cross section of a steel wire \[(Y=2.0\times {{10}^{11}}N/{{m}^{2}})\]is \[0.1\ c{{m}^{2}}\]. The force required to double its length will be [MP PET 2002] |
A. | \[2\times {{10}^{12}}N\] |
B. | \[2\times {{10}^{11}}N\] |
C. | \[2\times {{10}^{10}}N\] |
D. | \[2\times {{10}^{6}}N\] |
Answer» E. | |