1.

The area of cross section of a steel wire \[(Y=2.0\times {{10}^{11}}N/{{m}^{2}})\]is \[0.1\ c{{m}^{2}}\]. The force required to double its length will be [MP PET 2002]

A. \[2\times {{10}^{12}}N\]
B. \[2\times {{10}^{11}}N\]
C. \[2\times {{10}^{10}}N\]
D. \[2\times {{10}^{6}}N\]
Answer» E.


Discussion

No Comment Found

Related MCQs