The activity of one decay per second is equal to

1.	The activity of one decay per second is equal to
A.	1 atm
B.	1 Bq
C.	1 Cd
D.	1 mol
Answer» C. 1 Cd

Discussion

No Comment Found

Related MCQs

A musician using an open flute of length 50 cm produces second harmonic sound waves. A person runs towards the musician from another end of a hall at a speed of 10 km/h. If the wave speed is 330 m/s, the frequency heard by the running person shall be close to:
If the argument 'ωt' of the periodic function f(t) = A cos(ωt + φ) is increased by integral multiple of ______ radians, the value of the function remainsthe same.
A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by:
Oscillation of a particles is prescribed by the equation x = 3cos (0.25 πt), where is the time in seconds. The time taken by the particle to move from position of equilibrium to maximum displacement is
A pendulum clock be taken from the earth to a revolving artificial satellite, it will:
If 'x' is the displacement of a particle performing simple harmonic motion, then "kx2/2" is equal to its ______________ energy.
A resonance tube is old and has jagged end. It is still used in the laboratory to determine velocity of sound in air. A tuning fork of frequency mark near the open end of the tube. The 512 Hz e produces first resonance when the tube is filled with water to a mark 11 cm below a reference experiment is repeated with another fork of frequency 256 Hz which produces first resonance when water reaches a mark 27 cm below the reference mark. The velocity of sound in air, obtained in the experiment is close to
______________ motion is the projection of uniform circular motion on a diameter of the circle in which the latter motion takes place.
In the simple harmonic motion x = √2 sin(ωt – π/4), the phase constant can be shown as?
A simple pendulum is made of a string of length l and a bob of mass m, is released from a small angle θ0. It strikes a block of mass M, kept on a horizontal surface at its lowest point of oscillations, elastically. It bounces back and goes up to an angle θ1. Then, M is given by

The activity of one decay per second is equal to

Discussion

No Comment Found

Related MCQs

Reply to Comment