The accompanying sketch shows the schematic arrangement for measuring the thermal conductivity by the guarded hot plate method. Two similar 1 cm thick specimens receive heat from a 6.5 cm by 6.5 cm guard heater. When the power dissipation by the wattmeter was 15 W, the thermocouples inserted at the hot and cold surfaces indicated temperatures as 325 K and 300 K. What is the thermal conductivity of the test specimen material?

The accompanying sketch shows the schematic arrangement for measuring

1.	The accompanying sketch shows the schematic arrangement for measuring the thermal conductivity by the guarded hot plate method. Two similar 1 cm thick specimens receive heat from a 6.5 cm by 6.5 cm guard heater. When the power dissipation by the wattmeter was 15 W, the thermocouples inserted at the hot and cold surfaces indicated temperatures as 325 K and 300 K. What is the thermal conductivity of the test specimen material?
A.	0.81 W/m K
B.	0.71 W/m k
C.	0.61 W/m K
D.	0.51 W/m K
Answer» C. 0.61 W/m K

Discussion

No Comment Found

Related MCQs

“If β is less than zero, then with respect to the relation k = k0 (1 + β t), conductivity depends on surface area”.
The temperatures on the two sides of a plane wall are t1 and t2 and thermal conductivity of the wall material is prescribed by the relationK = k0 e (-x/δ)Where, k0 is constant and δ is the wall thickness. Find the relation for temperature distribution in the wall?
The unit of thermal conductivity doesn’t contain which parameter?
If β is greater than zero, then choose the correct statement with respect to given relationk = k0 (1 +β t)
The accompanying sketch shows the schematic arrangement for measuring the thermal conductivity by the guarded hot plate method. Two similar 1 cm thick specimens receive heat from a 6.5 cm by 6.5 cm guard heater. When the power dissipation by the wattmeter was 15 W, the thermocouples inserted at the hot and cold surfaces indicated temperatures as 325 K and 300 K. What is the thermal conductivity of the test specimen material?
With respect to the equation k = k0 (1 +β t) which is true if we put β = 0?
A plane wall of thickness δ has its surfaces maintained at temperatures T1 and T2. The wall is made of a material whose thermal conductivity varies with temperature according to the relation k = k0 T2. Find the expression to work out the steady state heat conduction through the wall?
The inner and outer surfaces of a furnace wall, 25 cm thick, are at 300 degree Celsius and 30 degree Celsius. Here thermal conductivity is given by the relationK = (1.45 + 0.5 * 10-5 t2) KJ/m hr degWhere, t is the temperature in degree centigrade. Calculate the heat loss per square meter of the wall surface area?
‚Äö√Ñ√∂‚àö√ë‚àö‚à´If ‚âà√≠‚Äö√¢¬ß is less than zero, then with respect to the relation k = k0 (1 + ‚âà√≠‚Äö√¢¬ß t), conductivity depends on surface area‚Äö√Ñ√∂‚àö√ë‚àöœÄ.$#
The unit of thermal conductivity doesn‚Äö√Ñ√∂‚àö√ë‚àö¬•t contain which parameter?#

Discussion

No Comment Found

Related MCQs

Reply to Comment