

MCQOPTIONS
Saved Bookmarks
1. |
The 3 – sigma upper limit for a control chart for average number of nonconformities per unit, is expressed by ___________ |
A. | UCL=\(\bar{u} + 3\sqrt{\frac{\bar{u}}{n}}\) |
B. | UCL=\(\bar{u} – 3\sqrt{\frac{\bar{u}}{n}}\) |
C. | UCL=\(\bar{u} – 2\sqrt{\frac{\bar{u}}{n}}\) |
D. | UCL=\(\bar{u} – \frac{3}{2} \sqrt{\frac{\bar{u}}{n}}\) |
Answer» B. UCL=\(\bar{u} – 3\sqrt{\frac{\bar{u}}{n}}\) | |