\[\tan \frac{A}{2}\]is equal to

1.	\[\tan \frac{A}{2}\]is equal to
A.	\[\pm \sqrt{\frac{1-\sin A}{1+\sin A}}\]
B.	\[\pm \sqrt{\frac{1+\sin A}{1-\sin A}}\]
C.	\[\pm \sqrt{\frac{1-\cos A}{1+\cos A}}\]
D.	\[\pm \sqrt{\frac{1+\cos A}{1-\cos A}}\]
Answer» D. \[\pm \sqrt{\frac{1+\cos A}{1-\cos A}}\]

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\[\tan \frac{A}{2}\]is equal to

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