\[{{\sum\limits_{k=1}^{n}{k\left( 1+\frac{1}{n} \right)}}^{k-1}}=\] [E – McqOptions

MCQOPTIONS

1.	\[{{\sum\limits_{k=1}^{n}{k\left( 1+\frac{1}{n} \right)}}^{k-1}}=\] [EAMCET 2002; Pb. CET 2002]
A.	\[n(n-1)\]
B.	\[n(n+1)\]
C.	\[{{n}^{2}}\]
D.	\[{{(n+1)}^{2}}\]
Answer» D. \[{{(n+1)}^{2}}\]

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