Specific volume of cylindrical virus particle is \[6.02\times {{10}^{-2}}cc/g.\] whose radius and length are 7 \[\overset{\text{o}}{\mathop{\text{A}}}\,\] & 10 \[\overset{\text{o}}{\mathop{\text{A}}}\,\] respectively.If \[{{N}_{A}}=6.02\times {{10}^{23}}mo{{l}^{-1}}\] find molecular weight of virus

\[3.08\times {{10}^{3}}kg/mol\]

\[3.08\times {{10}^{4}}kg/mol\]

\[1.54\times {{10}^{4}}kg/mol\]

Specific volume of cylindrical virus particle is \[6.02\times {{10}^{-

1.	Specific volume of cylindrical virus particle is \[6.02\times {{10}^{-2}}cc/g.\] whose radius and length are 7 \[\overset{\text{o}}{\mathop{\text{A}}}\,\] & 10 \[\overset{\text{o}}{\mathop{\text{A}}}\,\] respectively.If \[{{N}_{A}}=6.02\times {{10}^{23}}mo{{l}^{-1}}\] find molecular weight of virus
A.	\[3.08\times {{10}^{3}}kg/mol\]
B.	\[3.08\times {{10}^{4}}kg/mol\]
C.	\[1.54\times {{10}^{4}}kg/mol\]
D.	\[15.4kg/mol\]
Answer» E.

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Specific volume of cylindrical virus particle is \[6.02\times {{10}^{-2}}cc/g.\] whose radius and length are 7 \[\overset{\text{o}}{\mathop{\text{A}}}\,\] & 10 \[\overset{\text{o}}{\mathop{\text{A}}}\,\] respectively.If \[{{N}_{A}}=6.02\times {{10}^{23}}mo{{l}^{-1}}\] find molecular weight of virus

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