1.

Simplify the given grammar:
S->aXb

A. nX->aXb | e
B. S->aXb | ab, X-> aXb | ab
C. S->X | ab, X-> aXb | ab
D. S->aXb | ab, X-> S | ab
E. None of the mentioned
Answer» B. S->aXb | ab, X-> aXb | ab


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