Reynolds analogy is given by

1.	Reynolds analogy is given by
A.	Nu <sub>x</sub>/ (Re <sub>x</sub>) (Pr <sub>x</sub>) = 5 St <sub>X</sub> = ‚Äö√Ñ√∂‚àö√ë‚àö¬® 2 C <sub>F x </sub>
B.	Nu <sub>x</sub>/ 2 (Re <sub>x</sub>) (Pr <sub>x</sub>) = 4 St <sub>X</sub> = ‚Äö√Ñ√∂‚àö√ë‚àö¬® C <sub>F x </sub>/3
C.	Nu <sub>x</sub>/ (Re <sub>x</sub>) (Pr <sub>x</sub>) = St <sub>X</sub> = ‚Äö√Ñ√∂‚àö√ë‚àö¬® ¬¨¬®≈í¬© C <sub>F x </sub>
D.	Nu <sub>x</sub>/ (Re <sub>x</sub>) (Pr <sub>x</sub>) = 2 St <sub>X</sub> = ‚Äö√Ñ√∂‚àö√ë‚àö¬® C <sub>F x </sub>/4
Answer» D. Nu <sub>x</sub>/ (Re <sub>x</sub>) (Pr <sub>x</sub>) = 2 St <sub>X</sub> = ‚Äö√Ñ√∂‚àö√ë‚àö¬® C <sub>F x </sub>/4

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Reynolds analogy is given by

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