MCQOPTIONS
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| 1. |
Polar form of the Cauchy-Riemann equations is |
| A. | \(\dfrac{\partial u}{\partial r} = r \dfrac{\partial v}{\partial \theta} \ \text{and} \ \dfrac{\partial v}{\partial r}=-r \dfrac{\partial u}{\partial\theta }\) |
| B. | \(\dfrac{\partial u}{\partial r} = \dfrac{1}{r} \dfrac{\partial v}{\partial \theta} \ \text{and} \ \dfrac{\partial v}{\partial r}=-\dfrac{1}{r} \dfrac{\partial u}{\partial\theta }\) |
| C. | \(\dfrac{\partial u}{\partial r} = \dfrac{1}{r} \dfrac{\partial v}{\partial \theta} \ \text{and} \ \dfrac{\partial v}{\partial r}=-r \dfrac{\partial u}{\partial\theta }\) |
| D. | \(\dfrac{\partial u}{\partial r} = r \dfrac{\partial v}{\partial \theta} \ \text{and} \ \dfrac{\partial v}{\partial r}=- \dfrac{1}{r} \dfrac{\partial u}{\partial\theta }\) |
| Answer» C. \(\dfrac{\partial u}{\partial r} = \dfrac{1}{r} \dfrac{\partial v}{\partial \theta} \ \text{and} \ \dfrac{\partial v}{\partial r}=-r \dfrac{\partial u}{\partial\theta }\) | |