What will be the output of the program? public class ThreadDemo { private int count = 1; public synchronized void doSomething() { for (int i = 0; i < 10; i++) System.out.println(count++); } public static void main(String[] args) { ThreadDemo demo = new ThreadDemo(); Thread a1 = new A(demo); Thread a2 = new A(demo); a1.start(); a2.start(); } } class A extends Thread { ThreadDemo demo; public A(ThreadDemo td) { demo = td; } public void run() { demo.doSomething(); } }

It will print the numbers 1 to 20, but the order cannot be determined

It will print the numbers 0 to 19 sequentially

It will print the numbers 1 to 20 sequentially

What will be the output of the program? public class ThreadDemo { priv

1.	What will be the output of the program? `public class ThreadDemo { private int count = 1; public synchronized void doSomething() { for (int i = 0; i < 10; i++) System.out.println(count++); } public static void main(String[] args) { ThreadDemo demo = new ThreadDemo(); Thread a1 = new A(demo); Thread a2 = new A(demo); a1.start(); a2.start(); } } class A extends Thread { ThreadDemo demo; public A(ThreadDemo td) { demo = td; } public void run() { demo.doSomething(); } }`
A.	It will print the numbers 0 to 19 sequentially
B.	It will print the numbers 1 to 20 sequentially
C.	It will print the numbers 1 to 20, but the order cannot be determined
D.	The code will not compile.
Answer» C. It will print the numbers 1 to 20, but the order cannot be determined

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