On a base of 132 kV, 100 MVA, a transmission line has 0.2 per unit impedance. On a base of 220 kV, 50 MVA, it will have a per unit impedance of:

\(0.2*\frac{{100}}{{50}}*{\left( {\frac{{220}}{{132}}} \right)^2}\)

\(0.2*\frac{{50}}{{100}}*{\left( {\frac{{220}}{{132}}} \right)^2}\)

\(0.2*\frac{{100}}{{50}}*{\left( {\frac{{132}}{{220}}} \right)^2}\)

\(0.2*\frac{{50}}{{100}}*{\left( {\frac{{132}}{{220}}} \right)^2}\)

On a base of 132 kV, 100 MVA, a transmission line has 0.2 per unit imp

1.	On a base of 132 kV, 100 MVA, a transmission line has 0.2 per unit impedance. On a base of 220 kV, 50 MVA, it will have a per unit impedance of:
A.	\(0.2\frac{{50}}{{100}}{\left( {\frac{{220}}{{132}}} \right)^2}\)
B.	\(0.2\frac{{100}}{{50}}{\left( {\frac{{132}}{{220}}} \right)^2}\)
C.	\(0.2\frac{{50}}{{100}}{\left( {\frac{{132}}{{220}}} \right)^2}\)
D.	\(0.2\frac{{100}}{{50}}{\left( {\frac{{220}}{{132}}} \right)^2}\)
Answer» D. \(0.2\frac{{100}}{{50}}{\left( {\frac{{220}}{{132}}} \right)^2}\)