Moment of inertia of a triangle of base width ‘b’ and height ‘h� – McqOptions

MCQOPTIONS

1.	Moment of inertia of a triangle of base width ‘b’ and height ‘h’ with respect to the centroidal axis parallel to its base is equal to:
A.	\(\frac {bh^3}{12}\)
B.	\(\frac {bh^3}{18}\)
C.	\(\frac {bh^3}{24}\)
D.	\(\frac {bh^3}{36}\)
Answer» E.

Discussion

No Comment Found

Related MCQs

Polar radius of gyration for a circular lamina of diameter d is equal to
A rectangular section has 200 mm depth and 300 mm in width. Determine Moment of Inertia about the centroidal axis parallel to the width.
Moment of inertia of a circular area, whose diameter is d, about an axis perpendicular to the area, passing through its centre is given by:
Moment of inertia of a triangle of base width ‘b’ and height ‘h’ with respect to the centroidal axis parallel to its base is equal to:
Moment of inertia of a rectangular section having width (b) and depth (d) about an axis passing through its centre of gravity and parallel to the depth, is-
Moment of inertia of a rectangular plate of width b and height h about the centroidal axis is
A circular disc rolls down without slipping on an inclined plane. The ratio of its rotational kinetic energy to the total kinetic energy is
According to theorem of perpendicular axes, Ixx and Iyy be the M.I. of a lamina about xx and yy axis, then M.I. of the lamina about axis zz, which is perpendicular to xx and yy, equal to
Moment of inertia of hollow rectangular section having outer depth 'D' and breadth 'B' and dimensions of inner rectangle are depth ‘d’ and width 'b' about horizontal axis passing through centroid is:
A spherical shape has a diameter 'D', its moment of inertia (MI) will be -