\[\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{6}}^{{}^\circ }}+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{6}}^{{}^\circ }}+.......+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{8}{{\mathbf{4}}^{{}^\circ }}+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{8}{{\mathbf{5}}^{{}^\circ }}=\]?

\[\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{6}}^{{}^\circ }}+\ma

1.	\[\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{6}}^{{}^\circ }}+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{6}}^{{}^\circ }}+.......+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{8}{{\mathbf{4}}^{{}^\circ }}+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{8}{{\mathbf{5}}^{{}^\circ }}=\]?
A.	\[39\frac{1}{2}\]
B.	\[40\frac{1}{2}\]
C.	40
D.	\[49\frac{1}{\sqrt{2}}\]
Answer» C. 40

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\[\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{6}}^{{}^\circ }}+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}{{\mathbf{6}}^{{}^\circ }}+.......+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{8}{{\mathbf{4}}^{{}^\circ }}+\mathbf{si}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{8}{{\mathbf{5}}^{{}^\circ }}=\]?

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