Match the following: List-I List-II A. Circular sewer maximum discharge 1. Y= 0.938 D B. Maximum velocity in circular sewer 2. Y=0.81 D C. Triangular Channel 3. $${{y}_{c}}=\frac{4}{5}\,E,$$ $$\frac{v_{c}^{2}}{2g}=\frac{{{y}_{c}}}{4}$$ D. Bourdon gauge 4. $${{y}_{c}}=\frac{2}{3}\,E,$$ $$\frac{v_{c}^{2}}{2g}=\frac{{{y}_{c}}}{4}$$ Codes:

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TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

A$$\to $$4, B$$\to $$3, C$$\to $$2, D$$\to $$1

TuteeHUB · Answer

A$$\to $$3, B$$\to $$4, C$$\to $$1, D$$\to $$2

TuteeHUB · Answer

A$$\to $$2, B$$\to $$3, C$$\to $$1, D$$\to $$4

TuteeHUB · Answer

A$$\to $$1, B$$\to $$4, C$$\to $$2, D$$\to $$3

1.	Match the following: List-I List-II A. Circular sewer maximum discharge 1. Y= 0.938 D B. Maximum velocity in circular sewer 2. Y=0.81 D C. Triangular Channel 3. \[{{y}_{c}}=\frac{4}{5}\,E,\] \[\frac{v_{c}^{2}}{2g}=\frac{{{y}_{c}}}{4}\] D. Bourdon gauge 4. \[{{y}_{c}}=\frac{2}{3}\,E,\] \[\frac{v_{c}^{2}}{2g}=\frac{{{y}_{c}}}{4}\] Codes:
A.	A\[\to \]4, B\[\to \]3, C\[\to \]2, D\[\to \]1
B.	A\[\to \]3, B\[\to \]4, C\[\to \]1, D\[\to \]2
C.	A\[\to \]2, B\[\to \]3, C\[\to \]1, D\[\to \]4
D.	A\[\to \]1, B\[\to \]4, C\[\to \]2, D\[\to \]3
Answer» E.

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