Match Column I with Column II and select the con- answer with respect to hybridisation using the codes gr below: Column I (Complex) Column II (Hybridisation) (I) $${{[Au{{F}_{4}}]}^{-}}$$ (P) $$ds{{p}^{2}}$$hybridisation (II) $${{[Cu{{(CN)}_{4}}]}^{3-}}$$ (Q) $$ds{{p}^{3}}$$hybridisation (III) $${{[Cu{{({{C}_{2}}{{O}_{4}})}_{3}}]}^{3-}}$$ (R) $$s{{p}^{3}}\,{{d}^{2}}$$hybridisation (IV) $${{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}$$ (S) $${{d}^{2}}s{{p}^{3}}$$hybridisation Codes:

Question

TuteeHUB · Accepted Answer

(I)$$\to $$P,  (II)$$\to $$Q,  (III)$$\to $$R,  (IV)$$\to $$S

TuteeHUB · Answer

(I)$$\to $$Q,  (II)$$\to $$P,  (III)$$\to $$R,  (IV)$$\to $$S

TuteeHUB · Answer

(I)$$\to $$P,  (II)$$\to $$Q,  (III)$$\to $$S,  (IV)$$\to $$R

TuteeHUB · Answer

(I)$$\to $$Q,  (II)$$\to $$P,  (III)$$\to $$S,  (IV)$$\to $$R

1.	Match Column I with Column II and select the con- answer with respect to hybridisation using the codes gr below: Column I (Complex) Column II (Hybridisation) (I) \[{{[Au{{F}_{4}}]}^{-}}\] (P) \[ds{{p}^{2}}\]hybridisation (II) \[{{[Cu{{(CN)}_{4}}]}^{3-}}\] (Q) \[ds{{p}^{3}}\]hybridisation (III) \[{{[Cu{{({{C}_{2}}{{O}_{4}})}_{3}}]}^{3-}}\] (R) \[s{{p}^{3}}\,{{d}^{2}}\]hybridisation (IV) \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\] (S) \[{{d}^{2}}s{{p}^{3}}\]hybridisation Codes:
A.	(I)\[\to \]Q, (II)\[\to \]P, (III)\[\to \]R, (IV)\[\to \]S
B.	(I)\[\to \]P, (II)\[\to \]Q, (III)\[\to \]S, (IV)\[\to \]R
C.	(I)\[\to \]P, (II)\[\to \]Q, (III)\[\to \]R, (IV)\[\to \]S
D.	(I)\[\to \]Q, (II)\[\to \]P, (III)\[\to \]S, (IV)\[\to \]R
Answer» C. (I)\[\to \]P, (II)\[\to \]Q, (III)\[\to \]R, (IV)\[\to \]S

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