Linear acceleration of slider in the slider-crank mechanism may be expressed as:(where, r = radius of the crank, l = length of the connecting rod and $n = \frac{l}{r}$)

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TuteeHUB · Accepted Answer

$a = r{\omega ^2}\left[ {\sin \theta + \frac{{\sin 2\theta }}{n}} \right]$

TuteeHUB · Answer

$a = r{\omega ^2}\left[ {\cos \theta + \frac{{\sin 2\theta }}{n}} \right]$

TuteeHUB · Answer

$a = r{\omega ^2}\left[ {\cos \theta + \frac{{\cos 2\theta }}{n}} \right]$

TuteeHUB · Answer

$a = r{\omega }\left[ {\cos \theta + \frac{{\cos 2\theta }}{n}} \right]$

1.	Linear acceleration of slider in the slider-crank mechanism may be expressed as:(where, r = radius of the crank, l = length of the connecting rod and \(n = \frac{l}{r}\))
A.	\(a = r{\omega ^2}\left[ {\cos \theta + \frac{{\sin 2\theta }}{n}} \right]\)
B.	\(a = r{\omega ^2}\left[ {\cos \theta + \frac{{\cos 2\theta }}{n}} \right]\)
C.	\(a = r{\omega ^2}\left[ {\sin \theta + \frac{{\sin 2\theta }}{n}} \right]\)
D.	\(a = r{\omega }\left[ {\cos \theta + \frac{{\cos 2\theta }}{n}} \right]\)
Answer» C. \(a = r{\omega ^2}\left[ {\sin \theta + \frac{{\sin 2\theta }}{n}} \right]\)

Linear acceleration of slider in the slider-crank mechanism may be expressed as:(where, r = radius of the crank, l = length of the connecting rod and \(n = \frac{l}{r}\))

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