Let \[{{S}_{1}},{{S}_{2}}\] be the foci of the ellipse \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{8}=1.\]If \[A(x+y)\] is any point on the ellipse, then the maximum area of the triangle \[A{{S}_{1}}{{S}_{2}}\] (in square units) is

Let \[{{S}_{1}},{{S}_{2}}\] be the foci of the ellipse \[\frac{{{x}^{2

1.	Let \[{{S}_{1}},{{S}_{2}}\] be the foci of the ellipse \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{8}=1.\]If \[A(x+y)\] is any point on the ellipse, then the maximum area of the triangle \[A{{S}_{1}}{{S}_{2}}\] (in square units) is
A.	\[2\sqrt{2}\]
B.	\[2\sqrt{3}\]
C.	8
D.	4
Answer» D. 4

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Let \[{{S}_{1}},{{S}_{2}}\] be the foci of the ellipse \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{8}=1.\]If \[A(x+y)\] is any point on the ellipse, then the maximum area of the triangle \[A{{S}_{1}}{{S}_{2}}\] (in square units) is

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