Let \[f(x)=\left\{ \begin{align} & {{x}^{p}}\sin \frac{1}{x},x\ne 0 \\ – McqOptions

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1.	Let \[f(x)=\left\{ \begin{align} & {{x}^{p}}\sin \frac{1}{x},x\ne 0 \\ & 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,,x=0 \\ \end{align} \right.\] then \[f(x)\]is continuous but not differential at \[x=0\] if [DCE 2005]
A.	\[0<p\le 1\]
B.	\[1\le p<\infty \]
C.	\[-\infty <p<0\]
D.	p = 0
Answer» B. \[1\le p<\infty \]

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