Let \[f(x)\] be define on \[[-2,2]\] and is given by \[f(x)=\left\{ \begin{matrix} -1,\,-2\le x\le 0 \\ x-1,\,0\le x\le 2 \\ \end{matrix} \right.\], then \[f(\left| x \right|)\] is defined as

\[f(\left| x \right|)=\left\{ \begin{matrix} 1-2\le x\le 0 \\ 1-x,0

\[f(\left| x \right|)=x-1\forall x\in R\]

\[f(\left| x \right|)=\left\{ \begin{matrix} -x-1,-2\le x\le 0 \\ x-1,0

Let \[f(x)\] be define on \[[-2,2]\] and is given by \[f(x)=\left\{ \b

1.	Let \[f(x)\] be define on \[[-2,2]\] and is given by \[f(x)=\left\{ \begin{matrix} -1,\,-2\le x\le 0 \\ x-1,\,0\le x\le 2 \\ \end{matrix} \right.\], then \[f(\left\| x \right\|)\] is defined as
A.	\[f(\left\| x \right\|)=\left\{ \begin{matrix} 1-2\le x\le 0 \\ 1-x,0<x\le 2 \\ \end{matrix} \right.\]
B.	\[f(\left\| x \right\|)=x-1\forall x\in R\]
C.	\[f(\left\| x \right\|)=\left\{ \begin{matrix} -x-1,-2\le x\le 0 \\ x-1,0<x\le 2 \\ \end{matrix} \right.\]
D.	None of these
Answer» D. None of these

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Let \[f(x)\] be define on \[[-2,2]\] and is given by \[f(x)=\left\{ \begin{matrix} -1,\,-2\le x\le 0 \\ x-1,\,0\le x\le 2 \\ \end{matrix} \right.\], then \[f(\left| x \right|)\] is defined as

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