Let f(x) = 5 – |x – 2 | and g(x) = |x + 1|, x ∈ R. If f(x) attains maximum value at α and g(x) attains minimum at β, then \(\mathop {{\rm{lim}}}\limits_{x \to - \alpha \beta } \frac{{\left( {x - 1} \right)\left( {{x^2} - 5x + 6} \right)}}{{{x^2} - 6x + 8}}\) is equal to:

Let f(x) = 5 – |x – 2 | and g(x) = |x + 1|, x ∈ R. If f(x) attai

1.	Let f(x) = 5 – \|x – 2 \| and g(x) = \|x + 1\|, x ∈ R. If f(x) attains maximum value at α and g(x) attains minimum at β, then \(\mathop {{\rm{lim}}}\limits_{x \to - \alpha \beta } \frac{{\left( {x - 1} \right)\left( {{x^2} - 5x + 6} \right)}}{{{x^2} - 6x + 8}}\) is equal to:
A.	1/2
B.	-3/2
C.	-1/2
D.	3/2
Answer» B. -3/2

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Let f(x) = 5 – |x – 2 | and g(x) = |x + 1|, x ∈ R. If f(x) attains maximum value at α and g(x) attains minimum at β, then \(\mathop {{\rm{lim}}}\limits_{x \to - \alpha \beta } \frac{{\left( {x - 1} \right)\left( {{x^2} - 5x + 6} \right)}}{{{x^2} - 6x + 8}}\) is equal to:

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