Let f(x)= ( frac{x^{100}}{100}+ frac{x^{101}}{101}+ infty ). Find a p – McqOptions

MCQOPTIONS

1.	Let f(x)= ( frac{x^{100}}{100}+ frac{x^{101}}{101}+ infty ). Find a point c (- , ) such that f'(c) = 0
A.	1
B.	2
C.	0
D.	-1
Answer» D. -1

Discussion

No Comment Found

Related MCQs

Let f(x)= ( frac{x^{100}}{100}+ frac{x^{101}}{101}+ infty ). Find a point c (- , ) such that f'(c) = 0
A function f(x) with n roots should have n 1 unique Lagrange points.
Let f(x)= (x- frac{x^3}{3^2.2!}+ frac{x^5}{5^2.4!}- frac{x^7}{7^2.6!}+ infty ). Find a point nearest to c such that f'(c) = 1
For the infinitely defined discontinuous function<br> ( begin{cases}x+sin(2x)& :x in [0, pi] x+sin(4x)& :x in ( pi,2 pi] x+sin(6x)& :x in (2 pi,3 pi] . . x+sin(2nx)& :x in [(n-1) pi,n pi) . . end{cases} )
For a third degree monic polynomial, it is seen that the sum of roots are zero. What is the relation between the minimum angle to be rotated to have a Rolles point ( in Radians) and the cyclic sum of the roots taken two at a time c
What is the minimum angle by which the coordinate axes have to be rotated in anticlockwise sense (in Degrees), such that the function f(x) = 3x<sup>3</sup> + 5x + 1016 has at least one Rolles point
For the function f(x) = x<sup>3</sup> + x + 1. We do not have any Rolles point. The coordinate axes are transformed by rotating them by 60 degrees in anti-clockwise sense. The new Rolles point is?
For the function f(x) = x<sup>2</sup> 2x + 1. We have Rolles point at x = 1. The coordinate axes are then rotated by 45 degrees in anticlockwise sense. What is the position of new Rolles point with respect to the transformed coordinate axes?