Let \(f\left( z \right) = \frac{1}{{z + a}},\;a > 0\). The value of th – McqOptions

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1.	Let \(f\left( z \right) = \frac{1}{{z + a}},\;a > 0\). The value of the integral ∮ f(z) dz over a circle C with center (-a, 0) and radius R > 0 evaluated in the anti-clock wise direction is
A.	0
B.	2πi
C.	-2πi
D.	4πi
Answer» C. -2πi

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