MCQOPTIONS
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| 1. |
Let dq be the differential charge, dw be the differential energy. The rate of change of energy with time is given as: |
| A. | \(\frac{{dw}}{{dq}} \times \frac{{dq}}{{dt}}\) |
| B. | \(\frac{{dw}}{{dq}} + \frac{{dq}}{{dt}}\) |
| C. | \(\frac{{dw}}{{dq}}/\frac{{dq}}{{dt}}\) |
| D. | \(\frac{{dq}}{{dw}} \times \frac{{dq}}{{dt}}\) |
| Answer» B. \(\frac{{dw}}{{dq}} + \frac{{dq}}{{dt}}\) | |