Let \(Δ = \left| {\begin{array}{*{20}{c}} 1&{\sin \theta }&1\\ { - \sin \theta }&1&{\sin \theta }\\ { - 1}&{ - \sin \theta }&1 \end{array}} \right|\) The Δ lies in the interval

Let \(Δ = \left| {\begin{array}{*{20}{c}} 1&{\sin \theta }&1\\ { - \

1.	Let \(Δ = \left\| {\begin{array}{*{20}{c}} 1&{\sin \theta }&1\\ { - \sin \theta }&1&{\sin \theta }\\ { - 1}&{ - \sin \theta }&1 \end{array}} \right\|\) The Δ lies in the interval
A.	[3, 4]
B.	[2, 4]
C.	[1, 4]
D.	None of these
Answer» C. [1, 4]

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Let \(Δ = \left| {\begin{array}{*{20}{c}} 1&{\sin \theta }&1\\ { - \sin \theta }&1&{\sin \theta }\\ { - 1}&{ - \sin \theta }&1 \end{array}} \right|\) The Δ lies in the interval

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