Let d be the perpendicular distance from the centre of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] to the tangent drawn at a point P on the ellipse. If \[{{F}_{1}}\] and \[{{F}_{2}}\] be the foci of the ellipse, then \[{{(P{{F}_{1}}-P{{F}_{2}})}^{2}}=\]

\[{{a}^{2}}\left( 1-\frac{{{b}^{2}}}{{{d}^{2}}} \right)\]

\[4{{a}^{2}}\left( 1-\frac{{{b}^{2}}}{{{d}^{2}}} \right)\]

\[4{{a}^{2}}\left( 1-\frac{{{a}^{2}}}{{{d}^{2}}} \right)\]

\[{{b}^{2}}\left( 1-\frac{{{a}^{2}}}{{{d}^{2}}} \right)\]

Let d be the perpendicular distance from the centre of the ellipse \[\

1.	Let d be the perpendicular distance from the centre of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] to the tangent drawn at a point P on the ellipse. If \[{{F}_{1}}\] and \[{{F}_{2}}\] be the foci of the ellipse, then \[{{(P{{F}_{1}}-P{{F}_{2}})}^{2}}=\]
A.	\[4{{a}^{2}}\left( 1-\frac{{{b}^{2}}}{{{d}^{2}}} \right)\]
B.	\[{{a}^{2}}\left( 1-\frac{{{b}^{2}}}{{{d}^{2}}} \right)\]
C.	\[4{{a}^{2}}\left( 1-\frac{{{a}^{2}}}{{{d}^{2}}} \right)\]
D.	\[{{b}^{2}}\left( 1-\frac{{{a}^{2}}}{{{d}^{2}}} \right)\]
Answer» B. \[{{a}^{2}}\left( 1-\frac{{{b}^{2}}}{{{d}^{2}}} \right)\]

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Let d be the perpendicular distance from the centre of the ellipse \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1\] to the tangent drawn at a point P on the ellipse. If \[{{F}_{1}}\] and \[{{F}_{2}}\] be the foci of the ellipse, then \[{{(P{{F}_{1}}-P{{F}_{2}})}^{2}}=\]

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