Let \(\alpha {\rm{\;and\;}}\beta\) be the roots of the equationx2 + x +1 = 0. Then for y ≠ 0 in R,\(\left| {\begin{array}{*{20}{c}} {y + 1}&\alpha &\beta \\ \alpha &{y + \beta }&1\\ \beta &1&{y + \alpha } \end{array}} \right|\) is equal to:

Let \(\alpha {\rm{\;and\;}}\beta\) be the roots of the equationx2 + x

1.	Let \(\alpha {\rm{\;and\;}}\beta\) be the roots of the equationx2 + x +1 = 0. Then for y ≠ 0 in R,\(\left\| {\begin{array}{*{20}{c}} {y + 1}&\alpha &\beta \\ \alpha &{y + \beta }&1\\ \beta &1&{y + \alpha } \end{array}} \right\|\) is equal to:
A.	y(y2 – 1)
B.	y(y2 – 3)
C.	y3
D.	y3 – 1
Answer» D. y3 – 1