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1. |
Let \[a,b,c\] be real numbers \[a\ne 0\]. If \[\alpha \]is a root \[{{a}^{2}}{{x}^{2}}+bx+c=0\], \[\beta \] is a root of \[{{a}^{2}}{{x}^{2}}-bx-c=0\] and \[0<\alpha <\beta \], then the equation \[{{a}^{2}}{{x}^{2}}+2bx+2c=0\]has a root \[\gamma \]that always satisfies [IIT 1989] |
A. | \[\gamma =\frac{\alpha +\beta }{2}\] |
B. | \[\gamma =\alpha +\frac{\beta }{2}\] |
C. | \[\gamma =\alpha \] |
D. | \[\alpha <\gamma <\beta \] |
Answer» E. | |