Let \(A = \left[ {\begin{array}{*{20}{c}}2&b&1\\b&{{b^2} + 1}&b\\1&b&2\end{array}} \right]\) where b > 0. Then the minimum value of \(\frac{{det\left( {\rm{A}} \right)}}{{\rm{b}}}\)is:

Let \(A = \left[ {\begin{array}{*{20}{c}}2&b&1\\b&{{b^2} + 1}&b\\1&b&2

1.	Let \(A = \left[ {\begin{array}{*{20}{c}}2&b&1\\b&{{b^2} + 1}&b\\1&b&2\end{array}} \right]\) where b > 0. Then the minimum value of \(\frac{{det\left( {\rm{A}} \right)}}{{\rm{b}}}\)is:
A.	\(2\sqrt 3 \)
B.	\(- 2\sqrt 3\)
C.	\(- \sqrt 3 \)
D.	\(\sqrt 3 \)
Answer» B. \(- 2\sqrt 3\)