Let A be an n × n matrix from the set of numbers and A3 - 3A2 + 4A - 6I = 0 where I is an n × n unit matrix. If A-1 exists, then

\(A^{-1} = \dfrac{1}{6}(A^2 - 3A + 4I)\)

Let A be an n × n matrix from the set of numbers and A3 - 3A2 + 4A -

1.	Let A be an n × n matrix from the set of numbers and A3 - 3A2 + 4A - 6I = 0 where I is an n × n unit matrix. If A-1 exists, then
A.	A-1 = A - I
B.	A-1 = 3A - 6I
C.	A-1 = A + 6I
D.	\(A^{-1} = \dfrac{1}{6}(A^2 - 3A + 4I)\)
Answer» E.