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1. |
LCL for EWMA chart for Poisson distribution is written as ____________ |
A. | LCL=\(μ_0-A_L \sqrt{\frac{λμ_0}{2-λ}\big\{1-(1+λ)^{2i}\big\}}\) |
B. | LCL=\(μ_0+A_L \sqrt{\frac{λμ_0}{2-λ}\big\{1-(1+λ)^{2i}\big\}}\) |
C. | LCL=\(μ_0+A_L \sqrt{\frac{λμ_0}{2-λ}\big\{1-(1-λ)^{2i}\big\}}\) |
D. | LCL=\(μ_0-A_L \sqrt{\frac{λμ_0}{2-λ}\big\{1-(1-λ)^{2i}\big\}}\) |
Answer» E. | |