1.

\[\int_{0}^{\pi /2}{{{e}^{x}}\sin x\,dx=}\]  [Roorkee 1978]

A. \[\frac{1}{2}({{e}^{\pi /2}}-1)\]
B. \[\frac{1}{2}({{e}^{\pi /2}}+1)\]
C. \[\frac{1}{2}(1-{{e}^{\pi /2}})\]
D. \[2({{e}^{\pi /2}}+1)\]
Answer» C. \[\frac{1}{2}(1-{{e}^{\pi /2}})\]


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