#include using namespace std;class course{ char name[10]; public : void LFC() { cout

Question

#include <iostream>using namespace std;class course{   char name[10];  public : void LFC()  {     cout<<"Its course system";  }};class team : public course{    public: void LFC()    {       cout<<"Its team course system";    }};int main(){      team t;      t.LFC();}7.Can main() function be made private?

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

Yes, always

TuteeHUB · Answer

Yes, if program doesn't contain any classes

TuteeHUB · Answer

No, because main function is user defined

TuteeHUB · Answer

No, never

1.	#include <iostream>using namespace std;class course{ char name[10]; public : void LFC() { cout<<"Its course system"; }};class team : public course{ public: void LFC() { cout<<"Its team course system"; }};int main(){ team t; t.LFC();}7.Can main() function be made private?
A.	Yes, always
B.	Yes, if program doesn't contain any classes
C.	No, because main function is user defined
D.	No, never
Answer» E.

#include <iostream>using namespace std;class course{ char name[10]; public : void LFC() { cout<<"Its course system"; }};class team : public course{ public: void LFC() { cout<<"Its team course system"; }};int main(){ team t; t.LFC();}7.Can main() function be made private?

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#include &lt;iostream&gt;using namespace std;class course{ char name[10]; public : void LFC() { cout&lt;&lt;"Its course system"; }};class team : public course{ public: void LFC() { cout&lt;&lt;"Its team course system"; }};int main(){ team t; t.LFC();}7.Can main() function be made private?

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#include <iostream>using namespace std;class course{ char name[10]; public : void LFC() { cout<<"Its course system"; }};class team : public course{ public: void LFC() { cout<<"Its team course system"; }};int main(){ team t; t.LFC();}7.Can main() function be made private?