In the figure shown, the capacitor is initially uncharged. Which one of the following expressions describes the current I(t) (in mA) for

\(I\left( t \right) = \frac{5}{2}\left( {{e^{ - \frac{t}{\tau }}}} \right),\tau = \frac{2}{3}\;msec\)

\(I\left( t \right) = \frac{5}{3}\left( {1 - {e^{ - \frac{t}{\tau }}}} \right),\tau = \frac{2}{3}\;msec\)

\(I\left( t \right) = \frac{5}{3}\left( {1 - {e^{ - \frac{t}{\tau }}}} \right),\tau = 3\;msec\)

\(I\left( t \right) = \frac{5}{2}\left( {1 - {e^{ - \frac{t}{\tau }}}} \right),\;\tau = 3\;msec\)

In the figure shown, the capacitor is initially uncharged. Which one o

1.	In the figure shown, the capacitor is initially uncharged. Which one of the following expressions describes the current I(t) (in mA) for
A.	\(I\left( t \right) = \frac{5}{3}\left( {1 - {e^{ - \frac{t}{\tau }}}} \right),\tau = \frac{2}{3}\;msec\)
B.	\(I\left( t \right) = \frac{5}{2}\left( {{e^{ - \frac{t}{\tau }}}} \right),\tau = \frac{2}{3}\;msec\)
C.	\(I\left( t \right) = \frac{5}{3}\left( {1 - {e^{ - \frac{t}{\tau }}}} \right),\tau = 3\;msec\)
D.	\(I\left( t \right) = \frac{5}{2}\left( {1 - {e^{ - \frac{t}{\tau }}}} \right),\;\tau = 3\;msec\)
Answer» B. \(I\left( t \right) = \frac{5}{2}\left( {{e^{ - \frac{t}{\tau }}}} \right),\tau = \frac{2}{3}\;msec\)