 
			 
			MCQOPTIONS
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				| 1. | In the figure, initial voltage on C is V0S is closed at t = 0. The IL for t > 0 isWhere \(\omega _0^2 = 1/LC\) | 
| A. | -ω0 CV0 sin ω0 t | 
| B. | ω0 V0 sin ω0 t | 
| C. | -ω0 V0 sin ω0 t | 
| D. | ω0 CV0 sin ω0 t | 
| Answer» E. | |