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1. |
In the figure, initial voltage on C is V0S is closed at t = 0. The IL for t > 0 isWhere \(\omega _0^2 = 1/LC\) |
A. | -ω0 CV0 sin ω0 t |
B. | ω0 V0 sin ω0 t |
C. | -ω0 V0 sin ω0 t |
D. | ω0 CV0 sin ω0 t |
Answer» E. | |