1.

In the figure, initial voltage on C is V0S is closed at t = 0. The IL for t > 0 isWhere \(\omega _0^2 = 1/LC\)

A. -ω0 CV0 sin ω0 t
B. ω0 V0 sin ω0 t
C. -ω0 V0 sin ω0 t
D. ω0 CV0 sin ω0 t
Answer» E.


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