MCQOPTIONS
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| 1. |
In the figure given below, ABC is an isosceles triangle such that \[\mathbf{AB}=\mathbf{AC}\] and\[\angle \mathbf{B}=\mathbf{3}{{\mathbf{0}}^{{}^\circ }}\], AD is the median to the base BC. Then \[\Delta \mathbf{BAD}\] is: |
| A. | \[{{80}^{{}^\circ }}\] |
| B. | \[{{40}^{{}^\circ }}\] |
| C. | \[{{110}^{{}^\circ }}\] |
| D. | \[{{60}^{{}^\circ }}\] |
| Answer» E. | |