In TE mode of wave propagation in a rectangular waveguide, what is the equation that has to be satisfied?

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TuteeHUB · Accepted Answer

(‚Äö√Ñ√∂‚àö‚Ä†‚àö√°²/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x² + ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°²/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y²‚Äö√Ñ√∂‚àö√ë‚àö¬® kC²).HZ(x, y) =0

TuteeHUB · Answer

(‚Äö√Ñ√∂‚àö‚Ä†‚àö√°2/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x2 + ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°2/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y2+ kC2).HZ(x, y) =0

TuteeHUB · Answer

(‚Äö√Ñ√∂‚àö‚Ä†‚àö√°2/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x2 + ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°2/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y2‚Äö√Ñ√∂‚àö√ë‚àö¬® kC2).HZ(x, y) =0

TuteeHUB · Answer

(‚Äö√Ñ√∂‚àö‚Ä†‚àö√°2/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x2 ‚Äö√Ñ√∂‚àö√ë‚àö¬® ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°2/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y2+ kC2).HZ(x, y) =0

TuteeHUB · Answer

None of the mentioned

1.	In TE mode of wave propagation in a rectangular waveguide, what is the equation that has to be satisfied?
A.	(‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x<sup>2</sup> + ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y<sup>2</sup>+ kC<sup>2</sup>).HZ(x, y) =0
B.	(‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x<sup>2</sup> + ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y<sup>2</sup>‚Äö√Ñ√∂‚àö√ë‚àö¬® kC<sup>2</sup>).HZ(x, y) =0
C.	(‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x<sup>2</sup> ‚Äö√Ñ√∂‚àö√ë‚àö¬® ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y<sup>2</sup>+ kC<sup>2</sup>).HZ(x, y) =0
D.	None of the mentioned
Answer» B. (‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°x<sup>2</sup> + ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°<sup>2</sup>/ ‚Äö√Ñ√∂‚àö‚Ä†‚àö√°y<sup>2</sup>‚Äö√Ñ√∂‚àö√ë‚àö¬® kC<sup>2</sup>).HZ(x, y) =0

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