In system A vapours are superheated by \[10{}^\circ C\] in the evaporator while in system B vapours are superheated by \[10{}^\circ C\] in a liquid vapour regenerative heat exchanger, other conditions being the same. Then:

C.O.P. of both A and B > C.O.P. of Reversed Carnot Cycle

In system A vapours are superheated by \[10{}^\circ C\] in the evapora

1.	In system A vapours are superheated by \[10{}^\circ C\] in the evaporator while in system B vapours are superheated by \[10{}^\circ C\] in a liquid vapour regenerative heat exchanger, other conditions being the same. Then:
A.	C.O.P of A = COP of B
B.	C.O.P. of both A and B > C.O.P. of Reversed Carnot Cycle
C.	C.O.P. of A > C.O.P. of B
D.	C.O.P. of A < C.O.P. of B
Answer» D. C.O.P. of A < C.O.P. of B

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In system A vapours are superheated by \[10{}^\circ C\] in the evaporator while in system B vapours are superheated by \[10{}^\circ C\] in a liquid vapour regenerative heat exchanger, other conditions being the same. Then:

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