In drawing operation if \[{{D}_{i}}=\] initial diameter and \[{{D}_{0}}=\] outgoing diameter, then what is the degree of drawing equal to?

\[\sqrt{\frac{D_{i}^{2}-D_{0}^{2}}{D_{i}^{2}}}\]

\[\frac{{{D}_{i}}-{{D}_{0}}}{{{D}_{i}}}\]

\[\frac{D_{i}^{2}-D_{0}^{2}}{D_{i}^{2}}\]

In drawing operation if \[{{D}_{i}}=\] initial diameter and \[{{D}_{0}

1.	In drawing operation if \[{{D}_{i}}=\] initial diameter and \[{{D}_{0}}=\] outgoing diameter, then what is the degree of drawing equal to?
A.	\[\frac{{{D}_{i}}-{{D}_{0}}}{{{D}_{i}}}\]
B.	\[\frac{D_{i}^{2}-D_{0}^{2}}{D_{i}^{2}}\]
C.	\[\frac{D_{i}^{2}-D_{0}^{2}}{D_{i}^{2}}\]
D.	\[\sqrt{\frac{D_{i}^{2}-D_{0}^{2}}{D_{i}^{2}}}\]
Answer» D. \[\sqrt{\frac{D_{i}^{2}-D_{0}^{2}}{D_{i}^{2}}}\]

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In drawing operation if \[{{D}_{i}}=\] initial diameter and \[{{D}_{0}}=\] outgoing diameter, then what is the degree of drawing equal to?

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