In a viscously damped vibratory system with harmonic excitation, if \[{{\omega }_{1}}\] and \[{{\omega }_{2}}\] are the half power points, \[{{\omega }_{n}}\] is the natural frequency and \[\zeta \] is the damping factor, which one of the following is correct?

\[\frac{{{\omega }_{2}}+{{\omega }_{1}}}{{{\omega }_{n}}}=\zeta \]

\[\frac{{{\omega }_{2}}-{{\omega }_{1}}}{{{\omega }_{n}}}\]

\[\frac{{{\omega }_{2}}-{{\omega }_{1}}}{{{\omega }_{n}}}={{\zeta }^{2}}\]

\[\frac{{{\omega }_{2}}-{{\omega }_{1}}}{{{\omega }_{n}}}=\zeta \]

In a viscously damped vibratory system with harmonic excitation, if \[

1.	In a viscously damped vibratory system with harmonic excitation, if \[{{\omega }_{1}}\] and \[{{\omega }_{2}}\] are the half power points, \[{{\omega }_{n}}\] is the natural frequency and \[\zeta \] is the damping factor, which one of the following is correct?
A.	\[\frac{{{\omega }_{2}}-{{\omega }_{1}}}{{{\omega }_{n}}}\]
B.	\[\frac{{{\omega }_{2}}+{{\omega }_{1}}}{{{\omega }_{n}}}=\zeta \]
C.	\[\frac{{{\omega }_{2}}-{{\omega }_{1}}}{{{\omega }_{n}}}={{\zeta }^{2}}\]
D.	\[\frac{{{\omega }_{2}}-{{\omega }_{1}}}{{{\omega }_{n}}}=\zeta \]
Answer» B. \[\frac{{{\omega }_{2}}+{{\omega }_{1}}}{{{\omega }_{n}}}=\zeta \]

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In a viscously damped vibratory system with harmonic excitation, if \[{{\omega }_{1}}\] and \[{{\omega }_{2}}\] are the half power points, \[{{\omega }_{n}}\] is the natural frequency and \[\zeta \] is the damping factor, which one of the following is correct?

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