1.

In a triangle \[ABC,\,\,2{{a}^{2}}+4{{b}^{2}}+{{c}^{2}}=4ab+2ac,\] then\[\cos B\] is equal to

A. 0
B. \[\frac{1}{8}\]
C. \[\frac{3}{8}\]
D. \[\frac{7}{8}\]
Answer» E.


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