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1. |
In a triangle \[ABC,\,\,2{{a}^{2}}+4{{b}^{2}}+{{c}^{2}}=4ab+2ac,\] then\[\cos B\] is equal to |
A. | 0 |
B. | \[\frac{1}{8}\] |
C. | \[\frac{3}{8}\] |
D. | \[\frac{7}{8}\] |
Answer» E. | |