 
			 
			MCQOPTIONS
 Saved Bookmarks
				| 1. | Ignoring early effect, if C1 is the total capacitance tied to the emitter, what is the input pole of a simple C.B. stage? | 
| A. | 1/g<sub>m</sub> * C<sub>1</sub> | 
| B. | 2/g<sub>m</sub> * C<sub>1</sub> | 
| C. | g<sub>m</sub> * C<sub>1</sub> | 
| D. | g<sub>m</sub> * 2C<sub>1</sub> | 
| Answer» B. 2/g<sub>m</sub> * C<sub>1</sub> | |