1.

Ignoring early effect, if C1 is the total capacitance tied to the emitter, what is the input pole of a simple C.B. stage?

A. 1/g<sub>m</sub> * C<sub>1</sub>
B. 2/g<sub>m</sub> * C<sub>1</sub>
C. g<sub>m</sub> * C<sub>1</sub>
D. g<sub>m</sub> * 2C<sub>1</sub>
Answer» B. 2/g<sub>m</sub> * C<sub>1</sub>


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