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1. |
Ignoring early effect, if C1 is the total capacitance tied to the emitter, what is the input pole of a simple C.B. stage? |
A. | 1/g<sub>m</sub> * C<sub>1</sub> |
B. | 2/g<sub>m</sub> * C<sub>1</sub> |
C. | g<sub>m</sub> * C<sub>1</sub> |
D. | g<sub>m</sub> * 2C<sub>1</sub> |
Answer» B. 2/g<sub>m</sub> * C<sub>1</sub> | |