

MCQOPTIONS
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1. |
If \[y=x\sin x,\]then |
A. | \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}+\cot x\] |
B. | \[\frac{dy}{dx}=\frac{1}{x}+\cot x\] |
C. | \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}-\cot x\] |
D. | None of these |
Answer» B. \[\frac{dy}{dx}=\frac{1}{x}+\cot x\] | |