1.

If \[y=x\sin x,\]then    

A. \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}+\cot x\]
B. \[\frac{dy}{dx}=\frac{1}{x}+\cot x\]
C. \[\frac{1}{y}\frac{dy}{dx}=\frac{1}{x}-\cot x\]
D. None of these
Answer» B. \[\frac{dy}{dx}=\frac{1}{x}+\cot x\]


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