If \[y={{\sin }^{-1}}\sqrt{(1-x)}+{{\cos }^{-1}}\sqrt{x}\], then \[\frac{dy}{dx}=\]

If \[y={{\sin }^{-1}}\sqrt{(1-x)}+{{\cos }^{-1}}\sqrt{x}\], then \[\fr

1.	If \[y={{\sin }^{-1}}\sqrt{(1-x)}+{{\cos }^{-1}}\sqrt{x}\], then \[\frac{dy}{dx}=\]
A.	\[\frac{1}{\sqrt{x(1-x)}}\]
B.	\[\frac{-1}{\sqrt{x(1-x)}}\]
C.	\[\frac{1}{\sqrt{x(1+x)}}\]
D.	None of these
Answer» C. \[\frac{1}{\sqrt{x(1+x)}}\]