1.

If \[y={{\sin }^{-1}}\frac{2x}{1+{{x}^{2}}},\]where \[0

A. \[\frac{2}{1+{{x}^{2}}}\]
B. \[\frac{2x}{1+{{x}^{2}}}\]
C. \[\frac{-2}{1+{{x}^{2}}}\]
D. \[\frac{-x}{1+{{x}^{2}}}\]
Answer» B. \[\frac{2x}{1+{{x}^{2}}}\]


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