

MCQOPTIONS
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1. |
If \[x=\log p\]and \[y=\frac{1}{p}\], then |
A. | \[\frac{{{d}^{2}}y}{d{{x}^{2}}}-2p=0\] |
B. | \[\frac{{{d}^{2}}y}{d{{x}^{2}}}+y=0\] |
C. | \[\frac{{{d}^{2}}y}{d{{x}^{2}}}+\frac{dy}{dx}=0\] |
D. | \[\frac{{{d}^{2}}y}{d{{x}^{2}}}-\frac{dy}{dx}=0\] |
Answer» D. \[\frac{{{d}^{2}}y}{d{{x}^{2}}}-\frac{dy}{dx}=0\] | |